A body starts to slide over a horizontal surface with initial velocity of 0.2 m/s. Due to friction, its velocity decreases at a rate of 0.02 m/s^2. How much time will it take to stop?
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Answered by
6
Answer:
v = 0 ms-1
u = 0.2 ms-1
a = -0.02 ms-2
Substituting the values in the eq.
v = u + at
0 = 0.2 + (-0.02 x t)
t = 10 s
The body comes to rest after 10 s
Answered by
1
Answer:
Motion 1st law : v = u + at
u = 0.2m/s
a = -0.02m/s^2
v = 0
0 = 0.2 + (0.02)(t)
= 10 sec
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