A body starts to slide over a horizontal surface with an initial velocity of 0.5m/s. Due to friction, its velocity decreases at the rate of 0.105m/s to the power 2. How much time will body take to stop?
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Initial velocity = u = 0.5 m/s
final velocity = v = 0 m/s
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retardation = - 0.105 m/s²
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Now,
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Time = Change in velocity / retardation
= - 0.5 / - 0.105
= 500 / 105
= 4.67 s
_____________________________________________________________
Initial velocity = u = 0.5 m/s
final velocity = v = 0 m/s
______________________________________________________________
retardation = - 0.105 m/s²
______________________________________________________________
Now,
______________________________________________________________
Time = Change in velocity / retardation
= - 0.5 / - 0.105
= 500 / 105
= 4.67 s
_____________________________________________________________
yash199:
0.5 / 0.105 ma Kiya goya
hoya
bato
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