Question

a body starts to slide over a horizontal surface with an initial velocity of 0.5 m/s. due to friction its velocity decreases at the rate of 0.05 m/s*.how much time will it take for the body to stop

Answer 1

u=0.5 m/s
a=-0.05 m/s²
v=0
 By first equation of motion, we have:
 v=u+at
 0=0.5-0.05t
0-0.5=-0.05t
 -0.5=-0.05t
0.5/0.05=t
50/5=t
10 s=t

Answer 2

we know that

v = u +at

here

u = 0.5

a = -0.05 m/s2

v = 0 m/s

so, time taken to stop will be

t = -u/a = -0.5/-0.05

thus,
t = 10s

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