Question

A body starts to slide over a horizontal surface with an initial velocity of 0.5m/s. Due to friction it's velocity decreases at the rate of 0.05m/s^2. How much time will take for the body to stop?​

Answer 1

u=0.5 m/s

a=-0.05 m/s²

v=0

By first equation of motion, we have:

v=u+at

0=0.5-0.05t

0-0.5=-0.05t

-0.5=-0.05t

0.5/0.05=t

50/5=t

10 s=t

ıɬʑƈơɬɬơŋƈąŋɖყ65

Click here

Answer 2

Given:

Initial velocity (u) = 0.5 m/s

Rate of decrease in velocity/Retardation = -0.05 m/s²

Final velocity (v) = 0 m/s (Body stops)

To Find:

Time taken by body to stop (t)

Answer:

$\sf From \: 1^{st} \: equation \: of \: motion \: we \: have:$

$\boxed{ \boxed{ \bf{v = u + at}}}$

By substituting values in the equation we get:

$\rm \implies 0 = 0.5 + ( - 0.05)t \\ \\ \rm \implies 0.05t = 0.5 \\ \\ \rm \implies t = \dfrac{0.5}{0.05} \\ \\ \rm \implies t = 10 \: s$

$\therefore$ $\boxed{\mathfrak{Time \ taken \ by \ body \ to \ stop \ (t) = 10 \ s}}$