Question

A body starts to slide over a horizontal surface with an initial velocity of 0.5 m/s. Due to friction it decelerates at the rate 0.05 m/s2. How much time will it take for the body to stop?​

Answer 1

Answer:

Final velocity of the body v = 0 ms-1 as body comes to rest finally. Retardation of body = 0.05 ms-2. We know that v = u + at. T = 0.5/0.05 = 10 sec.

Answer 2

Given :-

☄ Intial velocity of the body (u) = 0.5 m/s

☄ Final velocity of the body (v) = 0 m/s

☄ Acceleration of thr body (a) = -0.05 m/s²

To Find :-

time taken by the body to stop

Solution :-

using equation of motion .i.e.,

➠ v = u + at

➠ 0 = 0.5 + (-0.05)(t)

➠ -0.5 = -0.05t

➠ t = 0.5/0.05

➠ t = 10sec.

thus, the time taken by the body to stop is 10sec.

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#Sanvi....