A body starts to slide over a horizontal surface with an initial velocity of 0.5m/s. Due to
friction its velocity decreases at the rate of 0.105 m/s2. How much time will it take for the body
to stop?
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Answered by
1
hey there
u = 0.5
v= 0
a = -0.105
t = ?
v = u +at
0 = 0.5 +(-0.105) * t
0.105 t = 0.5
t = 5/10 *1000/105
t = 100/21
t = 4.76 seconds :)
u = 0.5
v= 0
a = -0.105
t = ?
v = u +at
0 = 0.5 +(-0.105) * t
0.105 t = 0.5
t = 5/10 *1000/105
t = 100/21
t = 4.76 seconds :)
Answered by
0
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