Question

A body starts to slide over a horizontal surface with an initial velocity of 0.5m/s due to friction its velocity decreases at the rate of 0.105m/s square how much time will it take for the body to stop

Answer 1

Final Answer: 4.76s
Here,
Final velocity, v = 0 (to stop)
Initial velocity, u= 0.5m/s
acceleration, a =- 0.105m/s^2
Now,
v = u + at
=> 0 = 0.5 - 0.105t
=> t = 4.76 s

So, it will take 4.76s to stop the body

Answer 2

GIVEN:
Final Velocity (u) -> 0 [as it stops due to friction]
Initial Velocity (v) -> 0.5 m/s [given data]
Acceleration (a) -> 0.105 m/s² [given data].

TO FIND:
Time (t) -> ?

SOLUTION:

Using 1st Equation of Motion,
i.e. v = u + at
0 = 0.5 + 0.105(t)
-0.5 = 0.105t
-5/10 ÷ 105/1000 = t
t = 4.76190476190476....
therefore,
t = 4.8

hope it helps
Be Brainly