A body starts to slide over a horizontal surface with an initial velocity of 0.5 metre per second due to friction its velocity decreases at a rate of 0.5 m per second square how much time will it take for the body to stop
Answers
Answered by
4
According to an equation of kinematics for linear motion,
v= u+at, where, v is velocity at time t . We have to finnd t . u=0.5m/s, the initial velocity. a=-0.5 m/s^2 (retardation). When body stops moving ,v=0m/s. Substituting these values,
t=-(0.5/-0.5)=1s.
v= u+at, where, v is velocity at time t . We have to finnd t . u=0.5m/s, the initial velocity. a=-0.5 m/s^2 (retardation). When body stops moving ,v=0m/s. Substituting these values,
t=-(0.5/-0.5)=1s.
Answered by
1
Answer:
10s
Explanation:
v=u+at
0=0.2-0.02×t
0.02×t = 0.2
t=0.2/0.02
t=10sec
Similar questions