Question

a body starts to slide over a horizontal surface with an initial velocity of 0.5m/s due to friction its velocity decreases at the rate of 0.5m/s how much time will it take for the body to stop (10 sec
)

Answer 1

Given, u = 0.5 m/s

v = 0 m/s

a = -0.5m/s^2 (square)

t = ?

We know, a = (v-u)/t

or, t = (v-u)/a

or, t = (0-0.5)/-0.5

or, t = -0.5/-0.5

or, t = 1 second

The time required to stop the body is 1 second.

Answer 2

Answer:

1second

Explanation:u=0.5m/s

V=0m/s

A=0.5m/s

T=?

We already know that

A=(v-u) /t

T=(v-u)/a

T=(0.5)/0.5

T=0.5/0.5

T=1sec.