A body starts to slide over a horizontal surface with in a initial velocity 0.5m/Second due to friction its velocity decrease at the rate of 0.05 m/Sq how much will take for the body to stop
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if the system is under the force of friction and no other force is applied on it then, we use equation
v=u+at
v=0.5 m/sec.
u=0m/sec.
a=0.05m/sq
a is +ve because the direction of external force
then,
0.5=0+0.05 t
t=0.5/0.05
t=10sec
zarakhan11:
thanks
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