A body starts to slide over a horizontal surface with the initial velocity of .5m/s sq. Due to friction the velocity decreases at the rate of .05m/s sq. How much time will take for the body to stop.
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heya frnd
u=0.5 m/s
a=-0.05 m/s²
v=0
By first equation of motion, we have:
v=u+at
0=0.5-0.05t
0-0.5=-0.05t
-0.5=-0.05t
0.5/0.05=t
50/5=t
10 s=t
u=0.5 m/s
a=-0.05 m/s²
v=0
By first equation of motion, we have:
v=u+at
0=0.5-0.05t
0-0.5=-0.05t
-0.5=-0.05t
0.5/0.05=t
50/5=t
10 s=t
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