Question

a body starts up from rest and acquires a velocity of 8 in 5s

Answer 1

COMPLETE QUESTION:-

A body start up from rest and acquires a velocity of 8m/s in 5s. Calculate  

(a) the acceleration  

(b) the distance covered in 5s  

(c) the distance covered in 5th second.  

FINAL ANSWER:-

$(a)1.6m/s\\(b)20m\\(c)20m$

GIVEN:-

u=0m/s

v=8m/s

t=5s

TO FIND:-

(a) the acceleration  

(b) the distance covered in 5s  

(c) the distance covered in 5th second.  

FORMULAS USED:-

$v=u+at\\v^{2}=u^{2}+2as\\s=ut+ \frac{1}{2}at^{2}$

SOLUTION:-

Body starts from rest (u) = 0m/s

Than it acquires a velocity (v)=8m/s

Time taken by body (t)=5s

(a) by using $v=u+at$ let’s find Acceleration  

$8=0+5*a$[putting values in equation]

$5a=8\\a=\frac{8}{5}\\a=1.6m/s$

hence , acceleration of the body id 1.6m/s

(b) by using $v^{2}=u^{2}+2as$ let’s find distance

$8^{2}=0^{2}+2*1.6*s$ [← putting values in equation]

$64=0+3.2s\\3.2s=64\\s=\frac{64}{3.2}\\s=20m$

hence, distance travelled by body in 5 seconds is 20 meters

(c) by using $s=ut+ \frac{1}{2}at^{2}$ let’s find distance travelled in 5th second

$s=0*5+ \frac{1}{2}1.6(5)^{2}$ [← putting values in equation]

$s=0 + \frac{1}{2} *1.6 *25\\s=20m$

hence, distance travelled by body in 5th  seconds is 20 meters

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Here,

$v (final velocity)=8m/s\\u (initial velocity)=0m/s\\t (time taken)=5s\\a(acceleration)=1.6m/s\\s(distance)=20 meters$

Answer 2

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