Question

A body starts with a initial velocity of 10 m/s- and acceleration 5 find the distance covered in 5s​

Answer 1

Answer:

Second Equation of Motion

ut + 1/2at^2

u=10m/s

a= 5m/s^2

t=5secs

10 (5) + 1/2 (5)(5^2)

= 112.5m

Explanation:

Answer 2

Heya mate here is your answer

Given, U=10m/s

a=5m/s^2

t=5sec

As we know that , S=Ut+1/2at^2

=>S=10×5+1/2×5×(5)^2

S=50+1/2×5×25

S=50+1/2×125

S=50+125/2

S=100/2+125/2

S=225/2

S=112.5

Hope it helps

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