Question

A body starts with a velocity (29 +33 +118) m
m/sand moves with an acceleration of (5i + 5 3 – 5k) m
5k) m/s2. Its velocity after
02 sec in ms will be
(A) 77 + 8) + 6k
(B) 2i - 33 + 112
(C) 31 - 4 - 10
(D) 3i +49 + 10%​

Answer 1

Explanation:

A=v-u/t

10(i+j+k) = x - ( 2i - 3j + 11k )/2.5

x = 25(i+j+k) -2i +3j -11k ......... 2.5 * 10

= 25i-2i + 25j+3j + 25k+11k

= 23i + 28j + 36j

Q FROM VECTOR ??????

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