Question

A body starts with a velocity
(
2i + 3% + 11k) m/s and moves
with acceleration of
5i + 59 - 5k) m/s2. What is its
velocity after 0.2 sec ?​

Answer 1

Answer:

A body starts with a velocity (2i +3y +11k)m/s

Explanation:

the velocity is 3i+4j+10k

using the first equation of motion

v=u+at

we are given u,a,t and to find v

v=2i+3j+11k+0.2(5i+5j-5k)

v=2i+3j+11k+I+j-k

v=3i+4j+10k

hope it helps you

Answer 2

Answer:

the velocity is 3i + 4j + 10k

Explanation:

using the first equation of motion

v = u + at

we are given u , a , t and to find v

v = 2i + 3j + 11k + 0.2( 5i + 5j - 5k )

v = 2i + 3j + 11k + i + j - k

v = 3i + 4j + 10k