Question

A body starts with a velocity 2i - 3j + 11k m/s and moves with an acceleration of 10i +10j + 10k m/s 2 . What is its velocity after 0.2 s?

Answer 1

Answer:

4i - 3j + 13k

Explanation:

$motion \: of \: eq \\ v = u + at \\ v = (2i - 3j + 11k) + (10i + 10j + 10k) \times 0.2 \\ v = (2i - 3j + 11k) + (2i + 2j + 2k) \\ v = 2i - 3j + 11k + 2i + 2j + 2k \\ v = 4i - j + 13k \\ or \: v = \sqrt{185}$