Question

a body starts with a velocity of 40 metre per second and moves with an acceleration of 10 metre per second square find the distance travelled by the body in 15 seconds and the velocity at the end of the 15 second​

Answer 1

Answer:

Use kinematics to form an equation, and then just solve for d:

d = Vit + 1/2at^2

d = (40)(15) + 1/2(10)(15)^2

d = 1725 m

For the velocity, use another kinematic equation:

Vf^2 = Vi^2 + 2ad

Vf = sqrt(Vi^2 + 2ad)

Vf = sqrt((40)^2 + 2(10)(1725))

Vf = 190 m/s

Alternatively, if you know some very basic calculus, you could look at the first equation’s derivative which would give you velocity as a function of time:

d/dx( s(t) = Vit + 1/2at^2)

V(t) = Vi + 1/2(2)at

V(15) = 40 + (10)(15)

V(15) = 190 m/s

Which I believe is a more elegant way of showing it