Question

A body starts with a velocity of 40 ms and moves
with an acceleration of 10 ms-2. Calculate the
distance travelled by it in 15th second.​

Answer 1

Answer:

distance = 1725m

Explanation:

u=40m/s

a=10m/s^2

t=15sec

s=ut+1/2at^2

=40×15+1/2×10×15^2

=600+1125

=1725m

so,distance is 1725m

Answer 2

Answer:

Distance=1725

velocity at the end of the 15th second=190ms^-1