Question

A body starts with a velocity of 40m s-1 and moves with an acceleration of 10m s-2 the distance traveled by the body in 15 seconds and the velocity at the end of the 15th second is. Who give the answer bl Mark as brainlist and also say thanks plzz give ans fast

Answer 1

Given:

• initial velocity = 40 m /s
• acceleration = 10 m / s²
• time taken = 15 sec

To Find :

• total distance travelled by the body
• final velocity of the body

Solution:

As per the 2 nd kinematic equation ,

$\boxed{s = ut + \frac{a {t}^{2} }{2} }$

here ,

• s = distance
• u = initial velocity
• a = acceleration
• t = time taken

Substituting the above values in the given equation we get ,

$\implies{s = 40 \times 15+ \frac{10 \times 225}{2}}$

$\implies{s = 40 \times 15+ 5 \times 225}$

$\boxed{s =1725m}$

Now ,

Using the 1 st kinematic equation ,

$\boxed{v = u + at}$

here ,

• v = final velocity

$\implies{v = 40 + 10 \times 15}$

$\boxed{v = 190 \frac{m}{s} }$