Physics, asked by mramanavarma, 9 months ago

A body starts with a velocity of 60m s-1
moves with an acceleration of 20 m s-2. The
distance travelled by the body in 30 seconds
and the velocity at the end of the 30th second is (a) 1080 540ms-1. (B). 1080 190ms-1 (C) 1923ms-1. (D) 1080 660 ms-1​

Answers

Answered by komalbhaiyya
0

Answer:

According to the question,

Initial velocity = 60m/sec

Acceleration = 100m/sec

Time taken = 15 secondsDistance travelled = ?

According to the second equation of motion that is   S = ut + 1/2 Xat-2S = ( 60 X 15 ) + 1/2 X 100 X 15squareS = 900 + 1/2 X 100 X 225S = 900 + 1/2 X 22500S = 900 + 11250S = 12150

Hence , the distance travelled by the body in 15 seconds = 12150 metres

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Answered by vpatil20
0

Explanation:

option B

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