Question

A body starts with an inital velocity of 10 ms-1
and acceleration 5 ms-2 Find the distance covered by it in 5s

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Answer 1

Answer :-

• Distance covered = 112.5 meters

To Find :-

• The distance covered.

Given :-

• Initial velocity = 10 m/s

• Acceleration = 5 m/s²

• Time = 5 seconds

Step By Step Explanation :-

It is given that A body starts with an inital velocity of 10 m/s and acceleration 5 m/s² and time = 5 seconds.

We need to calculate the distance.

So, let's do it !!

Using first equation of motion ⤵

v = u + at

$\implies\tt{v = 10 + 5 \times 5} \\ \\\implies\tt {v = 10 + 25} \\ \\\implies\bf v = 35$

• Final velocity = 35

Using third equation of motion ⤵

v² - u² = 2as

$\implies\tt{(35)}^{2} - {(10)}^{2} = 2 \times 5 \times s \\ \\ \implies\tt1225 - 100 = 10s \\ \\ \implies\tt1125 = 10s \\ \\ \implies\tt \cfrac{1125}{10} = s \\ \\ \implies\bf112.5 = s$

Therefore distance covered = 112.5 meters.

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