Question

a body starts with an initial velocity 15/m/s and acceleration 4m/s2 . find the distance travelled by in 6s
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Answer 1

Answer:

$s = ut + \frac{1}{2} a {t}^{2} \\ \\ s = 15 \times 6 + 0.5 \times 4 \times {6}^{2} \\ \\ s = 90 + 72 \\ \\ s = 162 \: m$

answer will be = 162 m