Question

A body starts with an initial velocity if 10ms and acceleration 5m s^2
Find the distance covered by it in 5s.

Answer 1

Answer:

s= 112.5m

Explanation:

u= 10m/s

a= 5m/s^2

t= 5s

s= ut + 1/2at^2

s = 10*5 + 1/2*5*5*5

s= 50 + 62.5 m

s= 112.5m

Answer 2

Answer:

112.5 metres

Explanation:

s = ut + 1/2at^2(just a equation bro)

Where s = displacement or distance

           t = time

           u = initial velocity

           a = acceleration

s = ut + 1/2at^2

s = 10*5 + (1/2)5*5^2

s = 50 + (1/2)5*25

s = 50 + 2.5*25

s = 50 + 62.5

s = 112.5m

Conclusion

∴ displacement or distance travelled by the body = 112.5m