Question

A body starts with an initial velocity of 10 m s' and
acceleration 5 m s 2. Find the distance covered by
Ans. 112-5 m​

Answer 1

Answer:

Given,

Initial velocity (u) = 10m/s

Acceleration (a) = 5m/s²

Time (t) = 5sec

Distance (s) = ?

Using the 2nd equation of uniform motion,

s = ut + 1/2at²

s = 10(5) + 1/2 × 5 × (5)²

s = 50 + 62.5

s = 112.5

so,

The distance is 112.5 m .

Explanation:

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