Question

A body starts with an initial velocity of 10 ms-1 and acceleration 5 ms-2. Find the distance covered by it in 5 s.'

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 10 m/s

Acceleration, a = 5 m/s²

Time taken, t = 5 seconds.

To Find,

Distance covered, s = ?

We have to find the final velocity at first,

According to the 1st equation of motion,

We know that

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 10 + 5 × 5

⇒ v = 10 + 25

⇒ v = 35 m/s²

Here, the final velocity of body is 35 m/s².

Now, we will find thy distance covered, s,

According to the 3rd equation of motion,

We know that

v² - u² = 2as

So, putting all the values, we get

⇒ v² - u² = 2as

⇒ (35)² - (10)² = 2 × 5 × s

⇒ 1225 - 100 = 10s

⇒ 1125 = 10s

⇒ 1125/10 = s

⇒ s = 112.5 m

Hence, the distance covered by the body is 112.5 m.

Answer 2

${ \bold{ \huge{ \underline{ \blue { \underline{Question:-}}}}}}$




▪ A body starts with an initial velocity of 10m/sec and acceleration 5m/sec^2 . Find the distance covered by it in 5 sec.



${ \bold{ \huge{ \underline{ \blue{ \underline{Solution:-}}}}}}$



${ \dagger{ \bold{ \pink{ \: \: \: GIVEN- }}}}$




✯ initial velocity (u) = 10 m/sec



✯ acceleration (a) = 5 m/sec^2



✯ time (t) = 5 sec



${ \dagger{ \bold{ \pink{ \: \: \: TO \: FIND- }}}}$



➡ Distance covered??



${ \red{ \underline{ \bold{second \: equation \: of \: motion}}}}$



${ \boxed{ \boxed{ \bold{ \red{ \: \: \: S= ut + \frac{1}{2} a {t}^{2} \: \: \: }}}}}$



where,



• S = distance covered



• u = initial velocity



• t = time



• a = acceleration



▪ putting the above given values in the formula....



${ \bold{S = (10m \: {s}^{ - 1} )(5s) + \frac{1}{2} (5m {s}^{ - 2} )( {(5s)}^{2} )}}$



${ \bold{ \implies{S = 50 \: m \: + \frac{5\times25 \: m}{2}}}}$



${ \bold{ \implies{S = 50 \: m \: + \: 62.5 \: m}}}$



${ \boxed{ \bold{ \implies{ \pink{S = 112.5 \: m \: }}}}}$



therefore,



➡ The distance covered is 112.5 m