Question

A body starts with an initial velocity of 10 ms-1 and acceleration 7 ms-2

. Find the distance covered

by it in 5 s​

Answer 1

Answer:

Here's your answer

Explanation:

u = 10ms-1

a = 7ms-2

t = 5s

s = ut + 1/2 at^2

  = 10 x 5 + 1/2 x 7 x (2^2)

  = 50 + 1/2 x 7 x 4

  = 50 + 28/2

  = 50 + 14

  = 64m

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Answer 2

137.5m

Given:initial velocity(u)=10m/s

time(t)=5s

acceleration(a)=7m/s²

To find:displacement(s)

solution:From kinematical equation of motion,

s=ut+1/2at²

=10×5+1/2×7×(5)²

=50+87.5

=137.5m