Question

A body starts with an initial velocity of 10m/s and acceleration 5m/s^2 . find the distance covered by it in 5 s

Answer 1

Answer:

Distance = 0

Explanation:

S = ut-1/2at^2

S = 10*5-5*25

S = 0

Answer 2

Given:

• Initial velocity (u) = 10m/s
• Acceleration (a) = 5m/s²
• Time (t) = 5s

To find:

• The distance (s) covered by the body in 5 seconds.

Solution:

❐ By using first eqⁿ of motion,

• v = u + at

⇒ v = 10 + 5 × 5

⇒ v = 10 + 25

⇒ v = 35m/s

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❐ By using third eqⁿ of motion,

• v² - u² = 2as

⇒ (35)² - (10)² = 2 × 5 × s

⇒ 1225 - 100 = 10s

⇒ 1125 = 10s

⇒ s = 1125/10

⇒ s = 112.5m

Hence, the distance covered by the body in 5 seconds is 112.5m.

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