Question

A body starts with an initial velocity of 20 m/s and acceleration of 5 m s -2
.Find the distance covered by it in 5 s.​

Answer 1

Question:-

A body starts with an initial velocity of 20m/s and acceleration of 5m/s².Find the distance covered by it in 5s.

Solution:-

Given,

• A body starts with an initial velocity of 20m/s with an acceleration of 5m/s²It takes 5sec time then find the distance covered by the body.

Where,

• u = initial velocity
• v = final velocity
• a = acceleration
• s = distance
• t = time

We can find final velocity by using the first equation of motion:-

u = 20m/s ; a = 5m/s² ; t = 5sec ; v = ? ; s = ?

➣ v = u + at

➣ v = 20 + 5(5)

➣ v = 20 + 25

$\boxed{\bf{\color{yelow}{ \: v \: = \: 45m/s \: }}}$

Now,

We can find distance by using the third equation of motion:-

➣ s = ut + 1/2 at²

➣ s = 20(5) + 1/2 × 5 × 5 × 5

➣ s = 100 + 5 × 5 × 2.5

➣ s = 100 + 62.5

$\boxed{\bf{\color{yelow}{ \: s \: = \: 162.5m \: }}}$

Answer 2

Answer:

this is correct......................