Question

A body starts with an initial velocity u=2i+4j+2k and reaches a final velocity v=2i+6j-8k in 10 seconds its average acceleration will heHow to calculate average acceleration

Answer 1

Answer:

See in image.

Explanation:

See in image.

Answer 2

Answer:

Avg. acceleration =$\frac{\sqrt{26} }{5} m/sec$

Explanation:

Given

u=2i+4j+2k

the final velocity v=2i+6j-8k

time T= 10sec

To Find,

Avg. Acceleration

We know that,

v = u + at

So, by rearranging the formula, we get this for calculating acceleration vector

a = (v - u) / t

  =((2i+6j-8k)  -(2i+4j+2k))/10

  = 2i+6j-8k-2i-4j-2k

  = (2j -10k) / 10

  = (j -5 k) / 5

Hence, the  acceleration vector is  (j -5 k) / 5

Now Avg. acceleration can be found by

formula

$avg A=\sqrt{x^{2}+ y^{2} }$

$avg A=\sqrt{(1/5)^{2}+ 1^{2} }$

        $=\sqrt{26/25} \\=\frac{\sqrt{26} }{5}$

Avg. acceleration =$\frac{\sqrt{26} }{5} m/sec$

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