Question

a body starts with an initialvelocity of 20m/s and acceleration 5m/s2. find distance in. 5 sevonds​

Answer 1

Answer:

Initial velocity of body: 20m/s

acceleration of body: 5m/s sq.

Time: 5 seconds

To find distance in 5 seconds we will use second equation of motion:-

s = ut + 1/2 at^2

s = (20× 5) + 1/2 (5) (5^2)

s = 100 + 1/2 (5) (25)

s = 100 + 1/2 (125)

s = 100 + 125/ 2

s = 200+ 125/ 2 (By taking L.C.M)

s = 325/2

s= 162.5 m

Therefore, distance covered by the body in 5 seconds us 162.5 m.