Question

a body starts with an velocity 15 m/s and acceleration 2m/s2 find the distance travelled by it in 5s and 10 s

Answer 1

In 5 sec,
s=ut+1/2atsquare
s=15×5+1/2×2×5×5
s=75+25
s=100m
In 10 sec,
s=ut+1/2atsquare
s=15×10+1/2×2×10×10
s=150+100
s=250m

Answer 2

[1]
S = ut + 0.5at²
= (15 m/s × 5s) + (0.5 × 2 m/s² × (5 s)²)
= 100 m
Distance travelled in 5s is 100 m

[2]
S = ut + 0.5at²
= (15 m/s × 10s) + (0.5 × 2 m/s² × (10 s)²)
= 250 m
Distance travelled in 10s is 250 m