a body starts with initial speed u and moves in a straight line with constant acceleration. it has speed v after covering a distance 2s. its speed just after covering distance s is ...
Answers
Answered by
10
a=v^2-u^2/4s
speed after s h^2=u^2+2×a×s
h^2=u^2+v^2-u^2/2
h=under root ((u^2+v^2)/2)
speed after s h^2=u^2+2×a×s
h^2=u^2+v^2-u^2/2
h=under root ((u^2+v^2)/2)
RaoVishesh:
thanx bro..
Answered by
14
Answer:
The solution is here
See the attachment
Explanation:
Attachments:
Similar questions