A body starts with initial vel 0.5m/s.due to friction its velocity decreases at raté of 0.05m/s square. How much time Will it take for body to stop.
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we know v–u = at
here v=0
u=0.5m/s
a=–0.05m/s^2(– bcoz it is retardation or deaccelaration)
t= v–u/a=0–0.5/–0.05=50/5=10seconds
here v=0
u=0.5m/s
a=–0.05m/s^2(– bcoz it is retardation or deaccelaration)
t= v–u/a=0–0.5/–0.05=50/5=10seconds
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