Question

A body starts with initial velocity of 20 m/s and a retardation of 4 m/s2. The distance travelled by the body before it stops, is
O Zero
O 50 m
O 40 m
O 100 m​

Answer 1

Answer:

distance travel = 50 meters

Answer 2

Given:

A body starts with initial velocity of 20 m/s and a retardation of 4 m/s².

To find:

Distance travelled before it stops?

Calculation:

Applying 3rd Equation of Kinematics:

$\sf \: {v}^{2} = {u}^{2} + 2as$

$\sf\implies \: {0}^{2} = {(20)}^{2} + \{2 \times (- 4 )\times d \}$

$\sf\implies \: 0= 400 - 8d$

$\sf\implies \: 8d= 400$

$\sf\implies \: d= 50 \: m$

So, distance travelled is 50 metres.