Question

a body starts with initial velocity of 20m/s and a retardation of 4m/s^2 the distance travelled by body before it stops is​

Answer 1

Given:

A body starts with initial velocity of 20m/s and a retardation of 4m/s².

To find:

Distance before the body stopped?

Calculation:

Applying Equation of Kinematics:

${v}^{2} = {u}^{2} + 2as$

$\implies \: {0}^{2} = {20}^{2} + 2( - 4)s$

$\implies \: 0 = 400 - 8s$

$\implies \: 8s = 400$

$\implies \: s = 50 \: metres$

So, distance travelled before stopping is 50 metres.