Question

a body starts with initial velocity of 35 metres per second and produces an acceleration of 3 metre per second square for an interval of 7 seconds find the distance covered by the body in third second and fifth second​

Answer 1

answer=245 -7 seconds pls like me

Answer 2

Answer:

In the third second = 118.5 m & in the fifth second = 212.5 m

Explanation:

We know distance (S) = ut+1/2a(t) ²

S =( 35 × 3 ) + 1/2 × 3 × 3 × 3

S = 105 + 27/2

S = 237/2 = 118.5 m

So in the third secs(s) it travelled 118.5 m(s)

Now in the fifth second(s),

S = (35 × 5) + 1/2 × 3 × 5 × 5

S = 175 + 75/2

S = 212.5 m

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