Question

A body starts with velocity 36m/s and at the end of 10seconds it velocity increases to 96m/s.what is the acceleration

Answer 1

Solution

Initial velocity (u) = 36m/s

Final velocity (v) = 96m/s

Time = 10seconds

Acceleration = ?

By 1st equation of motion we have,

$\sf{v = u + at}$

$\sf \implies{a = \dfrac{v - u}{t} }$

$\sf \implies{a = \dfrac{96 - 36}{10} }$

$\sf \implies{a = \cancel\dfrac{60}{10}}$

$\sf\therefore{Acceleration={\underline{\boxed{\sf{6m/s².}}}}}$

Three Equations of Motion

v = u + at

s = ut + ½ at²

v² = u² + 2as.

Answer 2

$</p><p>\huge\mathbb\red{Solution}$

Initial velocity (u) = 36m/s

Final velocity (v) = 96m/s

Time = 10seconds

Acceleration = ?

By 1st equation of motion we have,

$\sf{v = u + at}v=u+at\sf \implies{a = \dfrac{v - u}{t} }$$\sf\implies{a = \dfrac{96 - 36}{10} }$$\sf\implies{a = \cancel\dfrac{60}{10}}$

∴ Acceleration = 6m/s².

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Three Equations of Motion

v = u + at

s = ut + ½ at²

v² = u² + 2as.