Physics, asked by shubhtripathi1438, 6 months ago

A body stretches a spring by a

particular length at earth’s surface
when suspended. At what height
above the earth’s surface the
elongation in the spring is half of its
initial value ?​

Answers

Answered by ak8811804
0

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Gravitation

Variation in Value of Acceleration due to Gravity

A body stretches a spring b...

PHYSICS

A body stretches a spring by a particular length at the earth's surface at equator.At what height above the south pole will it stretch the same spring by the same length? Assume the earth to be spherical.

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ANSWER

At equator g=g−ω

2

R...........(1)

Let at h height above the south pole,the acceleration due to gravity is same

Then,here g=(1−

R

2h

)...........(2)

g−ω

2

R=g(1−

R

2h

)

or1−

g

ω

2

R

=1−

R

2h

or h=

2g

ω

2

R

2

=

2×9.81

(7.3×10

−5

)

2

×(6400×10

3

)

2

=11125N=10Km(approximately)

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