a body takes 2 hours to move from point a to point b and 3h to come back.the distance between a and b is 200 km.find the average speed and average velocity
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Answered by
2
average speed of the body=total distance/total time
total distance= 200+200=400 km
total time= 2 hrs+3 hrs=5 hrs
avg speed= 400 km/5 hrs=80 km/hr=(80*5/18)m/s=22.22 m/s
avg velocity=0 since displacement= 200-200=0
total distance= 200+200=400 km
total time= 2 hrs+3 hrs=5 hrs
avg speed= 400 km/5 hrs=80 km/hr=(80*5/18)m/s=22.22 m/s
avg velocity=0 since displacement= 200-200=0
senthilk1999pa1mzc:
thnx
Answered by
0
Answer:
Total distance D=200+200=400 km
Average speed ∣V
avg
∣=
Total time
Total distance
∴ ∣V
avg
∣=
2+3
400
=80 km/h
Displacement S=0
Average velocity V
avg
=
Total time
Total displacement
∴ V
avg
=
2+3
0
=0 km/h
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