Question

A body takes 4 sec to fall from the top of a tower to the ground . Find the height of the tower of the value of uniform acceleration during falling period is 9.8 m/s square​

Answer 1

Answer:

I derived the answer by using the above equation.

Answer 2

s=u*t+1/2a*t^2

=0*4+1/2×9.8×4^2

=0+4.9×16

=78.4m