Question

A body thrown up reaches the highest point of flight in 3s. Calculate its initial velocity.​

Answer 1

Irrespective of mass H
max
​
=u
2
/2g=50m
if we double the initial velocity u then H
max
​
will get 4 times means 200m .

Answer 2

Answer:

u = 29.4 m/s

Explanation:

v = 0 ---—--—-— (body comes to rest at the top most point)

t = 3 s

g = 9.8 m/s

v = u+gt

on subs the values we get,

0 = u +(-9.8)*3

0 = u - 29.4

u = 29.4 m/s

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