Question

A body thrown up vertically reaches a maximum height of 100 m another body with double the mass thrown up with double the intial velocity will reach a maximum height of

Answer 1

Answer:400m

Explanation:let initial velocity = v

H=V^2/2g

100=v^2/20. (g=10 m/s)

V=√2000

Now

v' = 2v

Thus ,

H' =v'^2/2g =4v^2/20

=8000/20

=400

Answer 2

Let us first analyse the situation. Here, when the ball is thrown, air resistance is neglected. Therefore, no frictional force is acting. So, we can apply Conservation of Energy i.e sum of Kinetic and Potential will remain constant for the 2 balls.