A body thrown up vertically with a velocity of 19.6 ms-1. Find the maximum height reached and time of ascent.
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Answer:
A body projected vertically upwards with a velocity of 19.6ms−1 reaches a height of 19.6m on earth. If it is projected vertically up with the same velocity on moon, then the maximum height reached by it is (gearth=g ms−2, gmoon=6g ms−2)
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Explanation:
maximum height= u²/2g = 19.6×19.6/2×9.8
Hmax = 19.6m
time of ascent= u/g = 19.6/9.8 = 2s
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