Question

A body thrown up with a certain velocity reaches maximum height of 100m.find the maximum height of another velocity with double the mass thrown up with double the initial velocity

Answer 1

Answer:

400m

Explanation:

let initial velocity = v

H=V^2/2g

100=v^2/20. (g=10 m/s)

V=√2000

Now

v' = 2v

Thus ,

H' =v'^2/2g =4v^2/20

=8000/20 =400