Question

A body thrown up with a velocity reaches
maximum height of 100m. Another body with
double the mass thrown up with the same initial
velocity will reach the maximum height of??​

Answer 1

Answer:

Irrespective of mass H

max

=u

2

/2g=50m

if we double the initial velocity u then H

max

will get 4 times means 200m .

Answer 2

Answer:

A body reached a maximum height of 100m  another body with double the mass is thrown up with the same initial velocity the maximum height reached by it is  $100m$

Explanation:

• We have an equation of motion connecting initial velocity (u), final velocity (v), displacement (s), and acceleration(a) of a moving body as

         $V^{2} =u^{2} +2as$

• there is no terms regarding the mass of the body

• The final of a body at maximum height is zero

From the question, we have

maximum height reaches by the first body $s_{1}=100m$

⇒

$0=u^{2}+2a*100\\\frac{u^{2} }{2a} =100$

the initial velocity of the second body $=u$

⇒$0=(u)^{2} +2as_{2} \\\\s_{2} =u^{2}/2a =s_{1}=100m$

therefore the maximum height of the second body is $100m$