Question

A body thrown up with some initial velocity
reaches a maximum height of 50m. Another
body with double the mass thrown up with
double the initial velocity will reach a maximum
height of​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

A body is at a maximum height of 50m another body with double the mass is thrown up with the initial velocity twice that of the first body the maximum height reached by it is  $200m$

Explanation:

• We have an equation of motion connecting initial velocity (u), final velocity (v), displacement (s), and acceleration(a) of a moving body as

         $V^{2} =u^{2} +2as$

• there is no terms regarding the mass of the body

• The final of a body at maximum height is zero

From the question, we have

maximum height reaches by the first body $s_{1}=50m$

⇒

$0=u^{2}+2a*50\\\frac{u^{2} }{2a} =50$

the initial velocity of the second body $=2u$

⇒$0=(2u)^{2} +2as_{2} \\\\s_{2} =4(u^{2}/2a )=4*s_{1}=200m$

therefore the maximum height of the second body is $200m$