A body thrown upward reaches the highest point in 2.0 s. Find the velocity with which it was thrown.
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Answer:
ANSWER
v=u+at;a=−g
v=u−gt
v=0,u=gt
u=9.8×2=19.6 m/s
Explanation:
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Answered by
1
Explanation:
by the eqn: v = ut + 1/2 at ^2
= v = u+at ; a=−g
= v = u−gt
= v = 0, u=gt
= u = 9.8×2=19.6 m/s
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