Question

A body thrown upward rises to a height of 10 m and comes bsck to initial position

Answer 1

final velocity, v=m/s

$g = - 9.8m { \:s}^{2}$



(i) using formula,

$= v {}^{2} - {u}^{2 } = 2gs$
$= {o}^{2 } - {u}^{2} = 2 \times ( - 9.8) \times 10$
$= {u}^{2} = 196$
$= u = \sqrt{196} = 14 \frac{m}{s}$


U is the velocity with which the body is thrown upward .

(ii) Again,using the formula

V = U+gt

Time taken to the body to reach the higher point.

$t = \frac{v - u}{g} = \frac{0 - 14}{g} = 1.43sec$