A body thrown upwards with initial velocity 20m/s. Find the highest point that It will reach and the time to reach this altitude.
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Answered by
1
v = u - g t
0 = 20 - 10 t
t = 2 seconds. .
s = u t - 1/2 g t^2
s = 20*2 - 1/2* 10* 2^2 = 20 m
0 = 20 - 10 t
t = 2 seconds. .
s = u t - 1/2 g t^2
s = 20*2 - 1/2* 10* 2^2 = 20 m
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Answered by
1
Use the energy conservation formula here.
Potential energy=kinetic energy
mass x gravity x height= mass x velocity square x .5
mgh=mvv.5
gh=vv.5
10h=200
h=20
Potential energy=kinetic energy
mass x gravity x height= mass x velocity square x .5
mgh=mvv.5
gh=vv.5
10h=200
h=20
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