Question

a body thrown upwards with some velocity reaches the maximum height of 50m . Another body double the mass , thrown up with double the inital velocity will reach the maximum height of ?

Answer 1

Explanation:

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Answer 2

The maximum height reached by the second body is 200 meters.

Explanation:

A body thrown upwards with some velocity reaches the maximum height of 50 m. Its velocity can be calculated using conservation of energy as :

$v=\sqrt{2gh} \\\\v=\sqrt{2\times 10\times 50} \\\\v=31.622\ m/s$

The velocity of the another body is 2v i.e. 2 × 31.622 = 63.244 m/s

Again using the conservation of energy as :

$v=\sqrt{2gH}$

H is the maximum height reached by the second body.

$H=\dfrac{v^2}{2g}\\\\H=\dfrac{(63.244)^2}{2\times 10}\\\\H=199.99\ m$

or

H = 200 m

So, the maximum height reached by the second body is 200 meters.

Learn more,

Conservation of energy

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